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bezimeni [28]
3 years ago
10

on her way to visit her parents jennifer drives 265 miles in 5 hours, what is her avaerge rate of speed in miles per hour

Mathematics
1 answer:
telo118 [61]3 years ago
4 0
53 
265 divided by 5 equals 5
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Solve for r <br><br> 5-2(1-6r)=24
sammy [17]
You will get r= 21/12 but you have to simplify to get R=7/4 or R=1.75
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3 years ago
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If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Of 150 goldfish in the fish pound, 27 are red. What percentage of goldfish are red?
katovenus [111]

To get the percent, divide 27 by 150 then multiply the quotient by 100.

(27 / 150) * 100 = 18%

4 0
4 years ago
1. The following statement is false. Highlight the two words that should be
mafiozo [28]

Answer:

highlight input and output.

Step-by-step explanation:

sorry if this doesn't work. i'm not 100% sure but its worth a try.

4 0
3 years ago
I am not sure how to slove
notsponge [240]

First .... the limit of the given function is NOT EQUAL to 5 (it diverges so it has no limit).  There is a typo.  The 14 should be positive.

\lim_{x \to\ 7} \bigg(\dfrac{x^2-9x+14}{x-7}\bigg)=5

The precise definition of a limit is:

\text{If for every } \epsilon>0\text{ there exists a }\delta >0\text{ such that}\\|f(x)-L|

Given:

f(x) = \dfrac{x^2-9x+14}{x-7}\\\\L=5\\\\a=7\\\\\\|f(x)-L|

⇒ \epsilon = \delta

When ε = 0.1,     δ = 0.1

When ε = 0.01,   δ = 0.01

5 0
3 years ago
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