All categories

3 years ago

Food bill before tax: $30Sales tax: 6.4% Tip: 15%Please help!

Mathematics

1 answer:

Papessa [141]3 years ago

4 0

$30 x 0.064 = 1.92
$31.92 x .15 = 4.788
$31.92+4.788=
$36.708
Answer is $36.71

You might be interested in

A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard. Find a

vekshin1

Answer: $(13.28\%,\ 18.72\%)$

Step-by-step explanation:

Given : A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard.

i.e. n= 700 and x= 112

Sample proportion : $\hat{p}=\dfrac{x}{n}=\dfrac{112}{700}=0.16$

z-value for 95% confidence interval : $z_c=1.960$

Now, the 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard will be :-

$\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.16\pm (1.96)\sqrt{\dfrac{0.16(1-0.16)}{700}}$

$=0.16\pm (1.96)(0.013856)\\\\\approx 0.16\pm0.0272\\\\ =(0.16-0.0272,\ 0.16+0.0272)=(0.1328,\ 0.1872)=(13.28\%,\ 18.72\%)$

Hence, 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard : $(13.28\%,\ 18.72\%)$

6 0

3 years ago

50% of a box of cereal is less than 1/3 of a box of cereal true or false

SashulF [63]

Answer:

false

Step-by-step explanation:

1/3 is .3333 going on forever

so 50% is grater than 33%

6 0

3 years ago

Read 2 more answers

Who has the absolute advantage in bushes

Over [174]

Answer:Jensen

Step-by-step explanation:

6 0

3 years ago

Demarco has a piece of fabric 6yd long. He uses a piece 3yd long. He cuts the rest into strips that are each 3\4 yd long. How ma

Kobotan [32]

Answer: 4

Step-by-step explanation:

Hi, to answer this question, first, we have to subtract the amount of fabric used (3yd) to the total fabric that Demarco has (6yd)

6 -3 =3yd

Finally, we have to divide the result by the length of each strip piece (3/4yd)

3÷ 3/4= 4 pieces

There are 4 3/4 yd long strips.

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Given that k-5, k+7, k+55 are three consecutive terms in a geometric sequence, solve for k

choli [55]

Answer:

$k = 9$

Step-by-step explanation:

Given:

Consecutive Terms: k-5, k+7, k+55

Required:

Determine the value of k

To do this, we make use of the concept of common ratio.

The common ratio (r) of a geometric sequence is:

$r = \frac{T_{n}}{T_{n-1}}$

In other words:

$r = \frac{T_3}{T_2} = \frac{T_2}{T_1}$

Where 1, 2 and 3 represents the terms of the progression/sequence

So:

$r = \frac{T_3}{T_2} = \frac{T_2}{T_1}$ becomes

$\frac{k+55}{k+7} = \frac{k+7}{k-5}$

Cross Multiply:

$(k+55)(k-5) = (k+7)(k+7)$

Open Brackets

$k^2 + 55k - 5k - 275 = k^2 + 7k + 7k + 49$

$k^2 + 50k- 275 = k^2 + 14k + 49$

Collect Like Terms

$k^2 - k^2 + 50k-14k = 275 + 49$

$36k = 324$

Solve for k

$k = 324/36$

$k = 9$

5 0

3 years ago