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quester [9]
3 years ago
15

the doctor recommended that Matt increase the number of calories you consume from 2000 to 2800 by what percent did the number of

calories increase ​
Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:

40% number of calories have increased

Step-by-step explanation:

Old Value ( Calories consume before)  = 2000

New Value (increase in Calories consumed) = 2800

We need to find by what percent did the number of calories increase ​

To find percent increase, the formula used is:

Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100%

Putting values in formula and finding percent increase

Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100\%\:\\Percent\: increase=\frac{2800-2000}{2000}\times 100\%\: \\Percent\: increase=\frac{800}{2000}\times 100\%\: \\Percent\: increase=0.4\times 100\%\: \\Percent\: increase=40\%

So, 40% number of calories have increased

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S_A_V [24]

Answer:

12.53

Step-by-step explanation:

∠BCA = (180°-40°)/2 = 70°

Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°

CA = 5/sin 70° * sin 40° = 3.40

area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54

By Heron's Formula, area of triangle ABC:

1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6

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Entire region area = 4.54 + 7.99 = 12.53

5 0
2 years ago
If 2n - 7 = 5, what is the value of n?<br> *<br> A) 1<br> B) 6 <br> C) -1<br> D) 12
Contact [7]

The value of n is 6.

First, you must add 7 on both sides.

2n=12

Then, you must divide both sides by 2.

n=6

8 0
3 years ago
Find the arc length if the Central Angle is 340 and the Circumference is 6.​
GenaCL600 [577]

Answer:

17/3

Step-by-step explanation:

      To find the length of the arc, we have to find what fraction of the circle is the arc. To find this, we do 340/360 because there are 360 degrees in a circle, and get 17/18. Since the circumference is 6, we take 17/18 of 6 which is 17/3.

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3 years ago
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Anvisha [2.4K]

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Step-by-step explanation:

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Vinvika [58]

Answer:

that is correct

Step-by-step explanation:

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