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MaRussiya [10]
3 years ago
8

Mary is twice as old as Helen’s age, If 8 is subtracted from Helen’s Age and 4 is added to Mary Age? Mary will be 4 times as old

as Helen. What are the ages
Mathematics
1 answer:
erik [133]3 years ago
3 0

Answer:

set mary is x years old, and helen is y years old.

first sentence:x=2y

second one:4(y-8)=x+4

bring x=2y in 4(y-8)=x+4

=>4y-32=2y+4

=>2y=36

=>y=18

=>x=36

mary:36

helen:18

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Answer:

  P = 20000×1.625^(n/4)

Step-by-step explanation:

An exponential equation can be written using the given data:

  value = (initial value)×(growth factor in period)^(n/(period))

Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...

  P = 20000×1.625^(n/4)

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Kruka [31]

Answer:

C

Step-by-step explanation:

to evaluate substitute x = 0 and x = 1 into f(x)

note that a^{0} = 1

f(0) = 45 × (1/3)^{0} = 45 × 1 = 45

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Which expression is equivalent to x y Superscript two-ninths?
crimeas [40]

Option D: x\sqrt[9]{y^2} is the expression equivalent to xy^{\frac{2}{9}}

Explanation:

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The expression can be written as ({xy^9})^{\frac{1}{2}

Applying exponent rule, we get,

x^{\frac{1}{2}} y^{\frac{9}{2}}

Thus, the expression \sqrt{xy^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

Option C: x\sqrt{y^9}

The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

x y^{\frac{9}{2}}

Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

Option D: x\sqrt[9]{y^{2} }

The expression can be written as x(y^2)^{\frac{1}{9} }

Applying exponent rule, we get,

xy^{\frac{2}{9}}

Thus, the expression xy^{\frac{2}{9}} is equivalent to the expression xy^{\frac{2}{9}}

Hence, Option D is the correct answer.

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Mars2501 [29]

Answer:

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Then, plug the slope and a point into y = mx + b to solve for b:

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Plug the slope and the y intercept into the equation y = mx + b

y = 3.5x - 12.5 will be the equation

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