Answer:
12% of 60, 400% of 18, 55% of 220
Step-by-step explanation:
12% of 60 =7.2
55% of 220 = 121
400% of 18 = 72
7.2, 72, 121
...it’s 0.21 because 21% is 21/100 which makes it 0.21
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
The answer is B. Yes it is a triangle congruent
