Answer:
{10,8}
Step-by-step explanation:
-3x + 4y = -62
4x + 5y = 0
let's eliminate the x
-3x + 4y = -62 | x -4 |
4x + 5y = 0 | x 3 |
12x - 16y = 248
12x + 15y = 0
-------------------- -
-31y = 248
y = 248/(-31) = 8
since you must do this proble with elimination, we cant use subtitution. so we repeat the way once more to find x (eliminate y)
-3x + 4y = -62 | x 5 |
4x + 5y = 0 | x 4 |
-15x + 20y = -310
16x + 20y = 0
-------------------- -
-31x = -310
x = -310/-31 = 10
Answer:
42
Step-by-step explanation:
42-6 = 36
36*2 = 72
72-40 = 32
32/4 = 8
Answer:
Step-by-step explanation:
<u>Find the area of the garden:</u>
- A = 1/2bh
- A = 1/2(8)(15) = 60 m²
<u>Number of plants:</u>
Answer:
part A: Mean:6.42 Median:7
Part b: median
Part c: no it’s skewed left and unimodal
Step-by-step explanation:
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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