The slope of the line that passes through (1, -3) and (0, 2) is: B. m = -5.
<h3>What is the Slope of a Line?</h3>
Slope (m) = rise / run = change in y / change in x.
Given the points, (1, -3) and (0, 2):
Slope (m) = (-3 - 2)/(1 - 0)
Slope (m) = -5/1
Slope (m) = -5
Therefore, the slope of the line is: B. m = -5.
Learn more about the slope of a line on:
brainly.com/question/3493733
#SPJ1
Answer:
p=-9
Step-by-step explanation:
132=-6+3 (1-5p)
-6+3 (1-5p)=132
-6+3 (1-5p)+6=132+6
3(1-5p)=138
3(1-5p)/3=138/3
1-5p=46
1-5p-1=46-1
-5p=45
p=-9
Perimeter of quadrilateral ANCM = AN+NC+CM+MA
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in