Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12
The answer should be I think b
Answer:
Step-by-step explanation:
Given that:
R(x) = 
+ 34x − 17
As we know that derivative of revenue function is marginal revenue function .
We will use following rules of derivative
=> dR/ dx = 
=> R' (x) = 
=> R '(2000) = 
= 34
The revenue when 2000 units are sold is:
R(2000) = 
+ 34*2000 − 17 = $69,783
T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L
