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KIM [24]
2 years ago
6

Jack's and mo's orchard had a harvest of 450 ib and 1,215 ib of oranges respectively. If jack had 6 orange trees and mo had 15 o

range trees, whose orchard acquired the higher yield per tree?
Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
3 0

Answer:

  Mo

Step-by-step explanation:

The yield of Jack's trees was ...

  450 lb/(6 tree) = 75 lb/tree

The yield of Mo's trees was ...

  1215 lb/(15 tree) = 81 lb/tree

Mo's orchard had the higher yield per tree.

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ratelena [41]
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5 0
3 years ago
The side of rhombus is 14 in. The obtuse angle is 160º. Find the longer diagonal of the rhombus.
Mandarinka [93]

Answer:

x = 27.57 in to the nearest hundredth.

Step-by-step explanation:

The longer diagonal  is opposite the obtuse angle.

Also as it is a rhombus all sides = 14 in.

Use the Cosine Rule:

x^2 = 14^2 + 14^2 - 2*14^2 cos 160

x^2 =  760.36

x = sqrt 760.36

x = 27.57 in.

3 0
3 years ago
the larger of two positive numbers is 5 more then the smaller. The product of the numbers is 66. find the numbers
Serjik [45]

Answer: 30.5 and 35.5

Step-by-step explanation:

We can use a system of linear equations to find out the answer to this problem. The larger number will be x and the smaller number will be y.

x=y+5

x+y=66

Substitute y+5 in for the bottom equation to get y+5+y=66. Simplify to get 2y+5=66. Subtract 5 from both sides and get 2y=61. Divide by 2 to get y=30.5. This is the smaller number. Add 5 to get the bigger number, which is 35.5

7 0
3 years ago
A random sample of 64 observations produced a mean value of 84 and standard deviation of 5.5. The 90% confidence interval for th
ASHA 777 [7]

Answer:  The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

Step-by-step explanation:

When population standard deviation is not given ,The confidence interval population proportion is given by (\mu ):-

\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}

, where n= Sample size.

s= Sample standard deviation

\overline{x} = sample mean

t* = Critical t-value (Two-tailed)

As per given , we have

\overline{x}=84

n= 64

Degree of freedom : df = n-1=63  

s= 5.5

Significance level : \alpha=1-0.90=0.1

Two-tailed T-value for df = 63 and  \alpha=1-0.90=0.1 would be

t_{\alpha/2,df}=t_{0.05,63}=1.669  (By t-distribution table)

i.e. t*= 1.669

The 90% confidence interval for the population mean μ would be

84\pm (1.669)\dfrac{5.5}{\sqrt{64}}

=84\pm (1.669)\dfrac{5.5}{8}

\approx84\pm 1.15

=(84-1.15,\ 84+1.15)=(82.85,\ 85.15)

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

6 0
3 years ago
What is the mean of the values in the stem-and-leaf plot?
prisoha [69]

Answer:

You're answer is 42

Step-by-step explanation:

if you add all the numbers together, you would get 336. since there are eight numbers in the data set, you should divide it by eight.. with that said, 336/8 is 42

8 0
2 years ago
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