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Maurinko [17]
4 years ago
6

How many terms are in the expression x2 - 10xy + 3y + y2 - 1

Mathematics
1 answer:
Hatshy [7]4 years ago
7 0
There a five terms in this problem.
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The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche
Bezzdna [24]

Given:

Short sides of a rectangle = 2 inches.

Area of the rectangle = 22 square inches.

The long sides of the same rectangle are three less than an unknown number of inches.

To find:

The unknown number.

Solution:

Let x be the unknown number. Then the longer side of the rectangle is (x-3) inches.

We know that the area of a rectangle is

A=length\times width

The area of the rectangle is 22 square inches.

22=2(x-3)

Divide both sides by 2.

11=x-3

Add 3 on both sides.

11+3=x-3+3

14=x

Therefore, the value of the unknown number is 14.

3 0
3 years ago
Simplify <br> x^4+100^4 polynomials
LiRa [457]

Answer:

Solution,

x^4+100^4

x^4+100000000

Step-by-step explanation:

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7 0
3 years ago
4/5 + 2/3 in simplest terms
RSB [31]

Answer:

\frac{8}{15}

Step-by-step explanation:

1) use this rule: \frac{a}{b} × \frac{c}{d} =\frac{ac}{bd}

\frac{4*2}{5*3}

2) simplify 4 * 2 to 8

\frac{8}{5*3}

3) simplify 5 * 3 to 15

\frac{8}{15}

8 0
2 years ago
Mario is constructing a wall around a rectangular area which will cover a maximum of 60 square feet. The length of the wall will
Feliz [49]

Answer:

W \le 6

Step-by-step explanation:

Given

Area = 60ft^2\ (max)

Length = 10ft

Required

Represent the width as an inequality

First, we represent the area as an inequality.

Area = 60ft^2\ (max)

max as used above means less than or equal to.

So, we have:

Area \le 60

The area of a rectangle is:

Area = L * W

So, we have:

L * W \le 60

Substitute 10 for L

10 * W \le 60

Divide both sides by 10

\frac{10 * W}{10} \le \frac{60}{10}

W \le \frac{60}{10}

W \le 6

7 0
3 years ago
State 2 advantages of thermal expansion​
enot [183]

Answer:

Adaptable Refrigerant Flow.

Keeps the Evaporator Active and in Optimal Performance.

Higher Power Efficiency.

Eliminates Risk of Compressor Breakdown.

Handles Variation in Refrigerant Charge.

Better Temperature Control.

6 0
3 years ago
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