810/2= 405
810/3= 270
810/4= 202.5 (not this one)
810/5= 162
810/6= 135
810/7= 115.71 ( not this one)
810/8= 101.25 (not this one)
810/9= 90
810/10= 81
810/11= 73.63 (not this one)
I hope this helps you!
Answer:
1/ 3
Step-by-step explanation:
If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:
=> P(E) = number of cards of the required type/ total number of cards
● Total number of spades( ♤ ) = 3
{the queen, one ace and the nine are all spades}
● Total number of cards = 6
Probability of drawing a spade= 3/ 6
= 1/ 2
● Total number of "7" = 1
● Total number of cards = 6
Probability of drawing a 7
= 1/ 6
Now, what's asked is the difference in the probabilities of drawing a spade and a seven.
= 1/ 2 - 1/ 6
= 3/ 6 - 1/ 6
= 2/ 6
= 1/ 3
Hence, 1/ 3 of a greater chance of drawing a spade over a 7.
Answer:
4/49
Step-by-step explanation:
7-5 = 2
2/7*2/7 = 4/49
Terminating and Repeating Decimals. Any rational number (that is, a fraction in lowest terms) can be written as either a terminating decimal or a repeating decimal . Just divide the numerator by the denominator . If you end up with a remainder of , then you have a terminating decimal.