1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saw5 [17]
3 years ago
9

HELP QUICK PLEASEE THANKS

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0
(-9)+(-4) = -13

the answer is C
Ratling [72]3 years ago
5 0
The answer would be -13
You might be interested in
Helllllp >_< Compare: 1.2057 O 1.1421
vladimir2022 [97]

Answer:

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative controls

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative control

Step-by-step explanation:

6 0
3 years ago
Find the total surface area of a trapezoidal prism.
Ostrovityanka [42]
Split the trapezium into a rectangle and a triangle and work out the areas of them.
4x6=24
(2x4)/2=4
Area of trapezium= 28
There are 2 trapeziums, which makes 56.
The back of the shape is 4x14=56.
The top of the shape is 6x14=84.
The underside of the shape is 8x14=112.
The front rectangle is 14x4.47= 62.58.

As them all together= 56+56+84+112+62.58=370.58.

Total surface area=370.58.

Hope this helps :)
4 0
3 years ago
Read 2 more answers
1. Mr. Miller is building a dollhouse
Lina20 [59]

Answer:

1 ft : 2.5 yd or 1 ft : 2 1/2 yd

Step-by-step explanation:

He wants a real dimension of 10 yards to be represented by a scale dimension of 4 ft.

4 ft : 10 yd

Divide both sides by 4.

1 ft : 2.5 yd or 1 ft : 2 1/2 yd

8 0
3 years ago
Find x in the figure.<br><br><br> A) x = 44<br><br> B) x = 16<br><br> C) x = 22<br><br> D) x = 66
MakcuM [25]

Answer:

<h2>C)  x = 22</h2><h2 />

Step-by-step explanation:

3x + 3x + 48 = 180

6x = 180 - 48

x = 132 / 6

x = 22

7 0
2 years ago
Read 2 more answers
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
Other questions:
  • Hexagon ABCDEF has has vertices A(-2,4), B(0,4), C(2,1), D(5,1), E(5,-2), F(-2,-2). Sketch the figure on the coordinate plane. W
    10·1 answer
  • How do i identify the pairs of congruent angles in figures?
    7·1 answer
  • What is the interest on 350.00 invested 4 years at a 5% simple interest?
    12·1 answer
  • What is the solution to the system of equations represented by the two equations?
    7·1 answer
  • you are preparing breakfast platters for teacher appreciation week you are serving an equal number of muffins and bagels the muf
    6·1 answer
  • Which dimensions will create an unlimited number of triangles?
    6·2 answers
  • Lim of sin^2x/x as x approaches 0
    10·1 answer
  • Factorise yf -cg - yg+ cf​
    6·1 answer
  • write a rule that represents the function of these ordered pairs. (0,-8), (1,-7), (2,-6), (3,-5), (4,-4)
    5·1 answer
  • Determine the value of x.<br><br> No links please!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!