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schepotkina [342]
3 years ago
6

The distance from a point to two is five units. The point could be located at

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

do not no this

Step-by-step explanation:

mihalych1998 [28]3 years ago
3 0

Answer:

(0,7)

Step-by-step explanation:

Because if the point is 2 and the distance from that point is five units 2+5 = 7

I could also be 2-5 = -3

But it depends of which way you are moving left or right.

If you are moving to the left then it is -3

If you are moving to the right then it is 7

Hope this helps.

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Ab + 2b²<br> where<br> a = 7 b=4
Veronika [31]

Answer:

60

Step-by-step explanation:

a=7\\b=4\\ab+2b^2\\(7)*(4)+2*(4)^2\\28+2*16\\28+32\\=\fbox{60}

7 0
2 years ago
True of False: (log x)^2=2log x. Explain your answer and show your work
Lubov Fominskaja [6]
False.
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For example, let x=10
(log(10))^2=1^2=1
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8 0
3 years ago
For y = x^2 + 10x + 24, write the axis of symmetry, the vertex, and whether the
mylen [45]

Answer:

x= - 2

Step-by-step explanation:

hello :

note : the equation of the axis symmetry  for the parabola : y =ax²+bx+c

when :  a≠ 0 is : x=- b/2a

in this exercice : a=1  and b=10

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7 0
4 years ago
3 Gordon is selling popcorn that costs
riadik2000 [5.3K]

Answer:

30 more bags

Step-by-step explanation:

7 0
3 years ago
Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1
harkovskaia [24]
y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\&#10;y''(0)=20\cdot0^3=0

The value of the second derivative for x=0 is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of 5x^4 is always positive for x\in\mathbb{R}\setminus \{0\}. That means at x=0 there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval [-2,1].
The function y is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

y_{max}=y(1)=1^5-3=-2
4 0
3 years ago
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