Evaluate the following please.

Mathematics

1 answer:

Trava [24]3 years ago

4 0

(4•-1•-2^-2•2)(5•-1^-2•-2^3•2^-2)

(4•-1•1/4•2)(5•1•-8•1/4)
(-4•1/4•2)(5•-8•1/4)
(-2)(-40/4)
80/4 = 20

The answer is 20

You might be interested in

What is an equation of the line that passes through the points (0,2) and (5,8)

motikmotik

Answer: y= $\frac{6}{5}$ +2

Step-by-step explanation:

This is y intercept form

First you find the slope

Then you find the y intercept and plug it in t the equation y=mx+b

5 0

3 years ago

A tangent to a circle passes through the center of the circle True false sometimes true

liberstina [14]

Answer:

False.

Step-by-step explanation:

A tangent is a line that only touches exactly one point of the circle. (The outer edge) :)

8 0

3 years ago

Write y-4=3(x-2) in standard form (pls answer)

bearhunter [10]

in the y=mx+b form: y=3x-2

8 0

3 years ago

Divide and write the result in standard form: 3-i/1+5i

Ket [755]

We are asked to write the following fraction of complex numbers in standard form: $\displaystyle{ \frac{3-i}{1+5i}$ .

Whenever we are dividing by a complex number by another complex number a+bi, to write the result in standard form, we multiply the expressions in the numerator and denominator by the conjugate of a+bi, that is a-bi:

$\displaystyle{ \frac{3-i}{1+5i}= \frac{(3-i)(1-5i)}{(1+5i)(1-5i)}$

in the numerator we distribute (3-i) to 1 and -5i, in the denominator we use the difference of squares formula $(a-b)(a+b)=a^2-b^2$ , and $i^2=-1$ :

$\displaystyle{ \frac{(3-i)(1-5i)}{(1+5i)(1-5i)}= \frac{(3-i)\cdot1+(3-i)\cdot(-5i)}{1^2-(5i)^2}= \frac{3-i-15i-5}{1-25i^2}$

$\displaystyle{= \frac{-2-16i}{1+25}= \frac{-2-16i}{26}=-1/13-(8/13)i$

Answer: D

8 0

3 years ago

HELP. I have tried and tried and I CAN NOT solve these equations!

umka21 [38]

Here are the solutions. See the attachment. I've color-coded for clarity.

6 0

4 years ago