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zzz [600]
3 years ago
10

A restaurant charges $8 for a large cheese pizza plus $1.50 per topping. Another restaurant charges $11 for a large cheese pizza

plus $0.75 per topping. To find out how many toppings it would take for the pizzas to cost the same at both restaurants, which equation would you set up?
A. 8 + 1.5x = 11 + 0.75x
B. 8x + 1.5 = 0.75x + 11
C. 8 + 0.75x = 11 + 1.5x

Mathematics
1 answer:
Cloud [144]3 years ago
6 0
It would be A because in order to find out how much each topping would be you would need to multiply it by x or the number of toppings.
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PLS HELP AS SOON AS YOU CAN!!!....
N76 [4]

Answer:

I would say B because there are 15 1s


5 0
4 years ago
Lori needs at least 12 liters of water to fill a water cooler. She has a container with 4.55 liters of
Stels [109]

Answer:

<u></u>

  • <u>Yes, she has enough water.</u>

Explanation:

To <em>estimate</em> the value, you can work with friendly numbers: numbers closed to the given numbers and with which you can perform easy mental calculations.

For example 4.55 may be rouned to 5, 4.85 may be rounded to 5, and 3.25 may be rounded to 3. That yields 5 + 5 + 3 = 13

Then, it seems you have about 13 liters. Is the final number equal or greater than 12 for sure?

To round 4.55 to 5 you increased the amount in 0.45, to round 4.85 to 5 you increased the amount by 0.15, and to round 3.25 to 3 you decreased the amount in 0.25.

What was the net change in your values: 0.45 + 0.15 - 0.25 = 0.60 - 0.25 = 0.35. Those are easy calculations that you can perform in your mind.

That means that you increased your total in less than 1 liter. Meaning that the final total is overestimated by 0.35, and that if you used the real amounts to make the calculations, the total will be still more than 12.

4 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
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professor190 [17]
I can help you if you still!!!
4 0
2 years ago
BRAINLEST AND POINTS IF CORRECT
Natasha2012 [34]

Answer:

a. −1973700x

b. 0.12

c. 1344

d. − 36.2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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