So hmmm check the graph below
now.. to find the vertex of any quadratic

so... how long did it take? well, it took

what was the highest point? well, it was

when did he hit the water? well, at y = 0
that is

solve for "t"
Distance between A and B
= Distance between C and D
= sqrt((4 - 1)^2 + (5 - 2)^2)
= sqrt(3^2 + 3^2)
= sqrt(2 * 3^2)
= sqrt(3^2) * sqrt(2)
= 3sqrt(2)
Distance between B and C
= Distance between A and D
= sqrt((4 - 3)^2 + (5 - 0)^2)
= sqrt(1^2 + 5^2)
= sqrt(26)
Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).
Hope this helps you.
Answer:
Lisa must get an 88.75 or higher to stay in between 80 and 90.
Step-by-step explanation:
Answer:

Step-by-step explanation:
hello,
we can write

hope this helps
Answer:
1 Use Difference of Squares:
a^2-b^2=(a+b)(a−b).
10(x^2-4^2)
2 Simplify 4^2 to 16
10(x^2 −16)
3 Expand by distributing terms.
10x^2 −160
Step-by-step explanation:
Hope dis helps and pls mark me as brainlist!!!
§ALEX§