Question

A bowler getting strike during a particular frame has an estimated probability of 41%. If several simulations of the bowler bowling 2 frames were performed, what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames?
A. 61%
B. 38%
C. 18%
D. 81%

Answer 1

Answer:

Option C

Explanation:

Given -

The probability of a bowler getting a strike during a particular frame $= 41$ % $= 0.41$

Solution:

Probability of a bowler getting a strike during a particular frame is independent of frames.

Thus,

Probability of a bowler getting a strike during a single frame $= 41$ % $= 0.41$

Probability of a bowler getting a strike during a double frame

$= (\frac{41}{100} )^2\\= (0.41)^2\\= 0.41 * 0.41\\= 0.1681$

≈ $18%$ %

Answer 2

The percentage of simulations that the bowler would most likely get a strike in each of the two frames would be 18%. The correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your great help.