1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kipish [7]
4 years ago
14

The perimeter of an equillateral triangle is 63 inches. If the length of each side is (4x-3), find the value of x.

Mathematics
2 answers:
avanturin [10]4 years ago
6 0
Since all sides are congruent, the perimeter is 3 times the length of 1 side.

3(4x - 3) = 63

Divide both sides by 3:

4x - 3 = 21

Add 3 to both sides:

4x = 24

Divide both sides by 4:

x = 6
Nat2105 [25]4 years ago
4 0
Hello there,
1 side= (4x-3)
3 sides= (4x-3)3
           = (12x-9)
To find the value of x,
12x-9= 63
12x= 63+9
12x=72
x=6

On side note: Remember to change the sign when it crosses the equal sign. (for example: -2 will become 2 once it crosses the equal sign)

Hope this helps:))

~Top
You might be interested in
Mr and Mrs Kosley took their dog on a walk. Mr Kosley walks 5mph and Mrs Kosley walks 6mph. The dog walks 10mph. On the path, th
Nuetrik [128]

Answer:

ok boomer

Step-by-step explanation:

3 0
3 years ago
21y+7x=56? what is the value of X
PSYCHO15rus [73]

Answer:

x = 8 - 3y

Step-by-step explanation:

21y+7x=56\\\\21y-21y+7x=56-21y\\\\7x=56-21y\\\\\frac{7x=56-21y}{7}\\\\\boxed{x=8-3y}

Hope this helps.

4 0
3 years ago
Of 30 students 1/3 play sports. Of those who play sports 2/3 play soccer. How may students play soccer?
Orlov [11]

Answer:

4

Step-by-step explanation:

1/3 of 30 students play sport

30×1/3

= 10

2/5 of this number plays soccer

10×2/5

= 20/5

= 4

5 0
3 years ago
REALLY NEED HELP!!!<br> PLZ
Advocard [28]
Take a pic of whole page so I can see instructions
7 0
3 years ago
The following data was collected from the manufacturing of an auto component. It represents the diameter (in mm) of that compone
kari74 [83]

Answer:

14.6

Step-by-step explanation:

(A). STEP ONE: Calculate the mean

(1). Row one = (10 + 12 + 12 + 14 ) = 48/4 = 12.

(2). Row Two: (12 + 11 + 13 + 16 ) = 52/4 = 13.

(3). Row three : (11 + 13 + 14 + 14)/4 = 13.

(4). Row four: (11 + 10 + 7 + 8)/4 = 36/4 = 9.

(5). Row five: (13 +12 + 14 + 13)/4 = 52/4 = 13.

(B). STEP TWO:

- determine the maximum and minimum value for each row.

- for each row, maximum - minimum.

Maximum values for each row:

Row one = 14, row two= 16, row three = 14, row four = 11 and row five = 14.

Minimum value for each row:

Row one = 10, row two = 11, row three = 11, row four =7 and row five = 12.

DIFFERENCES in each row :

row one = 14 - 10 = 4, row two = 16 - 11 = 5, row three = 14 - 11 = 3, row four = 11 - 7 = 4 and row five = 14 -12 = 2.

(C). STEP THREE: Calculate the mean of all the rows = 60/5 = 12.

(D). STEP FOUR : Calculate the Average Range = 18/5 = 3.6.

(E). STEP FIVE : Calculate the UCL.

A = Average rage × 0.729 = 3.6 × 0.729.

B = overall mean = 12.

UCL = A + B = 14.6.

7 0
3 years ago
Other questions:
  • Select the correct product.
    7·1 answer
  • The amount of data left on a cell phone plan is 6 GB after B days 1.5 GB of data is used every day. How much data is available a
    15·1 answer
  • What is the slope of a line that passes through (1,77) and (3,40)
    14·1 answer
  • What are the x-intercept and y-intercept of the graph of y=−12x+4y=−12x+4 ?
    13·1 answer
  • What are all the triangles in geometry? And the angles too
    12·1 answer
  • Ignore the top part. <br> but can someone help me with part b please?
    8·1 answer
  • Please help I really dont understand
    7·1 answer
  • 8<br> What is 5.618372 rounded to the nearest tenths place?
    6·2 answers
  • Solve the following two problems using Calculus. Show all of your work on a separate sheet of paper, making clear how you arrive
    6·1 answer
  • Suppose we write down the smallest (positive) $2$-digit, $3$-digit, and $4$-digit multiples of $7$.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!