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1 year ago

If the length of a rectangle is three times it’s width and it’s parameter is 24cm what is the area

Mathematics

1 answer:

katrin [286]1 year ago

6 0

Answer:

Area = 27 cm²

Step-by-step explanation:

let L be the length of the rectangle

w the width

P the perimeter

A the area

Formulas :

P = 2×(L + w)

A = L × w

We are Given :

L = 3w

P = 2×(L + w)

⇔ 24 = 2×(3w + w)

⇔ 24 = 2×4w

⇔ 24 = 8w

⇔ w = 24/8 = 3

Then

L = 3w = 3×3 = 9

We obtain L = 9 and w = 3.

Then

A = L × w

= 9 × 3

= 27

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2 years ago

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$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

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= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

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= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

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Conclusion:-

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