5 hundreds times 10= Hundreds =
1 answer:
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Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Step-by-step explanation:
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:
Since we have given that
Using the poisson process, we get that
(a) less than or equal to 12
probability=
(b) equal to 13
probability=
(c) greater than 12
probability=
(d) equal to 20
probability=
(e) between 10 and 15, inclusively
probability=
Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318