Basically all you’re doing is plugging in the inputs to the equations and see if they’re correct.
5(3)+4(-3)=3 this proves to be true
2(3)-5(-3)=21 not 19
You did not attach any
picture to solve this problem. We cannot calculate for the value W’X’ without
the correct illustrations. However, I think I found the correct one (see
attached), please attach it next time.
So the first thing we have to
do is to calculate for the dilation factor. Taking point G as the reference
point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5
while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor
to use is:
dilation factor = 1.5 / (1.5
+ 7.5) = 1.5 / 9 = 1/6
Since WX has an initial
measure of 3 units, therefore the measure of W’X’ is:
W’X’ = 3 units * (1/6) = 0.5
units
Answer:
<span>0.5 units</span>
B because you don’t know exactly how many times she’s gonna grab the marbles
Answer:

Step-by-step explanation:
3/8 + 1/4 + 1/2 - 2/3
- > 1/4 = 2/8
3/8 + 2/8 + 1/2 - 2/3
5/8 + 1/2 - 2/3
- > 1/2 = 4/8
5/8 + 4/8 - 2/3
9/8 - 2/3
- > LCM of 8,3: 24
- > 9/8 = 27/24
- > 2/3 = 16/24
27/24 - 16/24
11/24
Hope this helps you.
Answer:
1) False
2) False
3) True
4) False
Step-by-step explanation:
1) Flase, {v1,v2,v3, ..., vp} is a base for H when they span H and also they are linearly independent.
2) False. A single nonzero vector is linearly independent , not dependent. There is not null linear combination that gives 0 as a result involving that vector.
3) True, if the columns werent linearly independent, we could triangulate the matrix and obtain 0, so the matrix wouldnt be invertible. This means that the columns should be linearly independent for the matrix to be invertible and as a consecuence, they will spam a subspace of R^n of dimension n, which means that they will spam all R^n and therefore, they form a basis of R^n.
4) False. A basis is a spanning set that is as small as possible. Larger spanning sets will have extra elements apart from those who can form a base toguether. Those elements will make the set linearly dependent.