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Setler79 [48]
4 years ago
8

Multiply express the answer.

Mathematics
1 answer:
MArishka [77]4 years ago
6 0
For this case, we have the following expression:
 4x (2x ^ 3 - x ^ 2-18x + 15)
 For this case, the first thing to do is multiply the value of 4x for each of the terms within the parenthesis.
 You must take into account the following power properties:
 Same exponents are added.
 We have then:
 (8x ^ 4 - 4x ^ 3-72x ^ 2 + 60x)
 Answer:
 
The standard form is:
 
(8x ^ 4 - 4x ^ 3-72x ^ 2 + 60x)
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PLEASE ASNWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!
lukranit [14]

Answer:

not sure but I feel like 6 because 3x2 is 6

3 0
3 years ago
please help me with this geometry homework. Oh and also I'm looking for a tutor a couple days a week so if you know anyone messa
sergij07 [2.7K]
The sum of the interior angles of an n gon is <span> (n-2)*180
the measure of each interior angle is </span><span>(n-2)*180/n
the measure of each individual exterior angle of an ngon is 360/n
all exterior angles add to 360

1. sum of 15 gon is
(15-2)*180=13*180=2340 degrees

2. deca is 10
(10-2)*180/10=8*18=144 degrees

3. dodecagon is 12 sides
360/12=30 degrees

4. 4 sides, those are exterior angles, so they add to 360
4r+7r+8r+5r=360
24r=360
r=15 degrees

5.
pentagon or 5 sides
sum of internal is (5-2)*180=3*180=540 degrees
540=4z+5z+3z+5z+3z
540=20z
27 degrees=z
3z=81=A=D
4z=108=B
5z=135=C=E

6. (n-2)*180
20 gon
(20-2)*180=18*180=3240 degrees

7. exterior angles add to 360
4y+2y+4y+6y=360
16y=360
y=22.5
2y=45 degrees
4y=90 degrees
6y=135 degrees

8. interior angles of 4 gon sum is
(4-2)*180=2*180=360
2n+6n+5n+2n=360
15n=360
n=24
2n=48
5n=120
6n=144

9.
6gon
(6-2)*180=4*180=720
90+90+x+x+22+x+x+22=720
224+4x=720
minus 224 both sides
4x=496
divide by 4
x=124


10., exterior angle of pentagon, 5 gon
360/5=72=x

11.
(n-2)*180/n=4*(360/n)
times both sides by n
(n-2)*180=4*360
divide both sides by 180
n-2=4*2
n-2=8
n=10
10 sides

12.
area of octogon of side is
</span>2(1+√2)s² where s is the side length
given, 12=side length
A=2(1+√2)12²
A=2(1+√2)144²
A=288(1+√2)
A=288+288√2 square cm
5 0
3 years ago
Drag the diagram that correctly models each description to the correct container.
bekas [8.4K]

Answer:

1/3 of 1/4 : Top left and 1/5 of 5/6: Top right

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B
riadik2000 [5.3K]

Let

S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n

where we assume |r| < 1. Multiplying on both sides by r gives

r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}

and subtracting this from S_n gives

(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}

As n → ∞, the exponential term will converge to 0, and the partial sums S_n will converge to

\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}

Now, we're given

a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a

a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}

We must have |r| < 1 since both sums converge, so

\dfrac{15}a = \dfrac1{1-r}

\dfrac{150}{a^2} = \dfrac1{1-r^2}

Solving for r by substitution, we have

\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)

\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}

Recalling the difference of squares identity, we have

\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}

We've already confirmed r ≠ 1, so we can simplify this to

\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15

It follows that

\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12

and so the sum we want is

ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0
3 years ago
6x+Q=Px+15 what values of P and Q result in an equation with exactly one solution?
NNADVOKAT [17]

P = 6

Q = 15

How to solve:

Note the equal sign. This means that both expression's out come must equal each other. For that to happen, everything inside both expressions must equal each other. In this case:

6x + Q = Px + 15; 6x + 15 = 6x + 15

hope this helps

8 0
4 years ago
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