Ask question

Ask question

All categories

3 years ago

5

Three-fourths of the people at a concert are children. If there are 87 children, what is the total number of people at the conce

rt?

2 answers:

babymother [125]3 years ago

8 0

Hello!

Let's write this as an equation below.

3/4x=87

To find our answer ,we just divide both sides of the equation by 3/4.

x=116

Therefore, 116 people attended the concert.

I hope this helps!

SSSSS [86.1K]3 years ago

4 0

Answer:

116 people

Step-by-step explanation:

At a concert the total number of children = 87

Children are 3/4 of the total number of people at the concert.

Let the total number of people be 'x'

Now the equation would be

$\frac{3}{4}x=87$

= ( $\frac{4}{3}$ ) × ( $\frac{3}{4}x$ ) = ( $\frac{4}{3}$ ) × (87)

x = 116

Therefore, the total number of people are 116 at the concert.

You might be interested in

Use the given information to find the new price. Round to the nearest cent. Original Price: $77.84 Discount Rate: 30%

Ghella [55]

$54.49 is the amount

7 0

2 years ago

Can anyone please help me with these

DochEvi [55]

Answer: Natural/Counting = 1, 0, 6, 3,

Whole = 1234, 135

Integers = -42,260, -97

Rational = 0.5432, 14.4, 6.2, 6.5892,

-14.4, 7.7777777, -13.574,

3.14, 0.4, 6.2, 0.4, 0.34,

12/6, -8/4, -10/5, -3/4, -3/8,

3/7, -4/8, 6/2, -8/4

Irrational = √34, -√34, -√ 36, 2π, √81,

√300, √1, π.

;Hope this Helped with both Pages:)

4 0

3 years ago

The full question is shown below

a_sh-v [17]

Answer:

n = 3

Step-by-step explanation:

Ratio from Triangle A to Triangle B is 2:1.

n+2 = 5

n = 3

8 0

3 years ago

Triangle A is the pre-image in a translation, and triangle B is the image, as shown below.

Lana71 [14]

B. Love miss you have you too she got your

8 0

2 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago