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kirza4 [7]
3 years ago
15

Solve for y: 4y - x = 64

Mathematics
2 answers:
MrRa [10]3 years ago
5 0

y 4y=64  4

y

=

64  Divide each term in 4

y

=

64   by   4  .  4

y  4  =

64  4

Reduce the expression by cancelling the common factors.

Tap for more steps...  y

=

64  4  Divide   64   by  4

.  y

=

16

omeli [17]3 years ago
4 0

Answer:

y=16

Step-by-step explanation:

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rosijanka [135]
HOPE THIS HELPS! IF IT DOESN'T...I'M SO SORRY! SORRY 4 REALLY BAD CAMERA QUALITY! :(
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6 0
3 years ago
A MILKMAN SOLD TWO OF HIS BUFFALOES FOR RS.20,000. EACH ON ONE HE MADE A GAIN OF 5% AND ON THE OTHER A LOSS OF 10%. FIND HIS OVE
Sveta_85 [38]
Selling price of 1st buffalo +Selling price of 2nd buffalo=20000
profit for 1st buffalo=0.05 of cost price of 1st buffalo
loss for 2nd buffalo=0.1 of cost price of 2nd buffalo
1.05(cost price of 1st buffalo)+(0.9)cost price of 2nd buffalo=20000
the buffalo must cost must be same = x (say)
1.05x+0.9x=20000
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4 0
3 years ago
A store is selling a TV for $389. This is %64 less than the regular price. What is the regular price?
nignag [31]
64%      =       $389
___                ____

100%                X$               = Cross multiplication. (64x = 38900 = $607.81)

I rounded it.

Hope I become the brainliest answer.

4 0
3 years ago
If you buy a school raffle ticket for $1, your overall probability of winning at least one of the prizes is 0.04. you can improv
ser-zykov [4K]
By buying 2 tickets you doubled the probability of you winning something. So, the probability that one of your tickets will win something is 0.08. Hope this helps :)
4 0
4 years ago
A painting company will paint this wall of a building. The owner gives him the following dimensions.
Masja [62]

The given area of the 52\frac{1}{2} ft. by 33 ft. wall less the areas of the Windows and the Door give the area of the painted part of the wall as  \underline{1642\frac{9}{16}} ft.²

<h3>How can the area of the painted part be calculated?</h3>

The area of the painted part of the wall is \underline{1642\frac{9}{16}} ft.²

The given dimensions of the wall are;

The width of the wall = 52\frac{1}{2} ft.

The height of the wall = 33 ft.

The painted area = Area of the wall - (Area of the widows + The door)

Which gives;

52\frac{1}{2} \times 33 - \left(6\frac{1}{4} \times 5\frac{3}{4} + 3\frac{1}{8} \times 4 + 9\frac{1}{2}  + 4 \times 8 \right) = \mathbf{ 1642 \frac{9}{16}}

The area of the painted part of the wall is \underline{1642\frac{9}{16}} ft.²

Learn more about the area of a rectangle here:

brainly.com/question/18101587

7 0
3 years ago
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