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Maurinko [17]
3 years ago
15

What is the pattern in this sequence?

Mathematics
2 answers:
Sladkaya [172]3 years ago
5 0

Answer in #1 it ads up by 8


malfutka [58]3 years ago
5 0

Number 1 is Add by 8

& I'm not sure about number 2


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Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec
vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}

Hence, we have:

\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\  \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}

Divide the expression for the fifth term by the expression for the second term:

\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}

Substituting the value of r into any of the expression:

\begin{gathered} ar\text{ =  18} \\ a\text{ }\times\text{ 2 =  18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}

Hence, the explicit rule for the sequence is:

a_n\text{ = 9\lparen2\rparen}^{n-1}

5 0
2 years ago
What is the total surface area of the pyramid below?
mel-nik [20]

Answer:I guess 6 ft as you gave same options

Step-by-step explanation:

8 0
3 years ago
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Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
3 years ago
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Given the recursive formula:<br> a1=3<br> An=2(an-1+1)<br> Find a2 a3 a4
fenix001 [56]

Answer:

a_2 = 8

a_3 = 18

a_4 = 38

Step-by-step explanation:

We are given the following recursive formula:

a_n = 2(a_{n-1}+1)

And consider a_1 = 3

a2

a_2 = 2(a_1 + 1) = 2(3 + 1) = 8

a3

a_3 = 2(a_2 + 1) = 2(8 + 1) = 18

a4

a_4 = 2(a_3 + 1) = 2(18 + 1) = 38

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3 years ago
Karissa is a vet tech who earns $9.64 per hour. What are her total
Ymorist [56]

Answer:

385.6

Step-by-step explanation:

The wage times the hours worked find the total she makes.

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3 years ago
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