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maw [93]
3 years ago
6

The owner of a 4000-gal oil truck loads the truck with gasoline and keroseno. The profit on each gallon of gasoline is 16e and o

n each gallon of kerosene it is 12¢. How many gallons of each fuel did the owner load it
the profit was $620?

There were___
gallons of gasoline and
___gallons of kerosene.
Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

There were 35 gallons of gasoline and 500 gallons of kerosene.

Step-by-step explanation:

<u>Step 1: Write data for equation 1</u>

<em>Let gallons of kerosene be x</em>

<em>Let gallons of gasoline be y</em>

<em>Total capacity of truck is 4000</em>

<u>Step 2: Form equation 1</u>

x + y = 4000

<u>Step 3: Write data for equation 2</u>

<em>Profit of total gallons of kerosene is 0.12x</em>

<em>Profit of total gallons of gasoline is 16y</em>

<em>Total profit is $620</em>

<u>Step 4: Form equation 2</u>

0.12x + 16y = 620

<u>Step 5: Find x in terms of y from equation 1</u>

x + y = 4000

x = 4000 - y

<u>Step 6: Substitute value of x in equation 2</u>

0.12x + 16y = 620

0.12 (4000 - y) + 16y = 620

480 - 12y + 16y = 620

4y = 620 - 480

y = 140/4

y = 35

<u>Step 7: Substitute value of y in equation 1 to find x</u>

0.12x + 16y = 620

0.12x + 16 ( 35 ) = 620

0.12x = 60

x = 500

There were 35 gallons of gasoline and 500 gallons of kerosene.

!!

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