Correct answer: Option D- DNA ligase
Explanation: In option A, thymine is a nucleotide, so it is present throughout the replication process, wherever it is required. It is added to the newly formed DNA. In option B, Helicase enzyme is active during initiation and elongation stage, as it facilitates the opening of the winded DNA strands. Option C is nucleotidase and it has no role in DNA replication. So, the correct answer is DNA ligase, which is option D.
The okazaki fragments formed during DNA replication are sealed at the end. And in this step, DNA ligase is used. It catalyzes the formation of phosphodiester bond between the nucleotides of okazaki fragments. So it is the last active molecule of the process.
Answer:
Genetic code is the term we use for the way that the four bases of DNA--the A, C, G, and Ts--are strung together in a way that the cellular machinery, the ribosome, can read them and turn them into a protein. In the genetic code, each three nucleotides in a row count as a triplet and code for a single amino acid.
Explanation:
Answer:
- 1/2 = 50% de la progenie será roja heterocigota, Rr
- 1/2 = 50% de la progenie será blanca homocigota recesiva, rr.
Explanation:
- El gen que codifica para el color de flor es dialélico
- El alelo R es dominante y expresa color rojo en homocigosis y heterocigosis.
- El alelo r es recesivo y expresa el color blanco en homocigosis.
Cruza: flores rojas heterocigotas con flores blancas
Parentales) Rr x rr
Fenotipo) Rojo Blanco
Gametas) R r r r
Cuadro de Punnett)
R r
r Rr rr
r Rr rr
F1) 2/4 = 1/2 = 50% de la progenie será roja heterocigota, Rr
2/4 = 1/2 = 50% de la progenie será blanca, rr.
The scientific method has five basic steps, plus one feedback step: Make an observation. Ask a question. Form a hypothesis, or testable explanation.