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3 years ago

5

Draw 3 rows with 2counters in each row.write a word problem that can be acted put using these counters.

1 answer:

serg [7]3 years ago

3 0

Jimmy is planting a garden he has 3 rows of carrots with 2 carrots in each row he has 6 carrots in total

And the drawing should look something like this
00
00
00

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Please Help I Will Mark Brainly.

Evgesh-ka [11]

Answer:

13

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Step-by-step explanation:

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2 years ago

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A machine makes 600 candies a minute. At this rate, how long will it take this machine to make 1800 boxes, each of which contain

Marta_Voda [28]

1800 boxes with 24 candies each

Total = 1800 * 24 = 43 200 candies

The machine makes 600 candies in 1 minute

   1 candy would take (1/600) minute

   43 200 candies would take 43200 * 1/600 = 72

   = 72 minutes.

Therefore the 1800 boxes would be done in 72 minutes.

3 0

2 years ago

The area of circular garden is 530.66 feet2. What is the circumference of the garden? (Use 3.14 for .

iVinArrow [24]

$\bf \textit{area of a circle}\\\\
A=\pi r^2\quad 
\begin{cases}
r=radius\\
------\\
A=530.66
\end{cases}\implies 530.66=\pi r^2
\\\\\\
\cfrac{530.66}{\pi }=r^2\implies \sqrt{\cfrac{530.66}{\pi }}=r
\\\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\qquad \implies C=2\pi \left( \sqrt{\cfrac{530.66}{\pi }} \right)$

3 0

2 years ago

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

>> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

>> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

3 0

2 years ago

Explain to me how to do this please

nataly862011 [7]

You must first attach the problems with your question.

6 0

3 years ago