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RUDIKE [14]
3 years ago
5

Help me out please 5x+4y=11 3x+5y=4 do this in elimination method (with working)

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

(5x+4y) - (3x+5y) = 11-4

5x - 3x + 4y = 5y = 7

2x - y = 7

4(2x - y) = 4*7

8x - 4y = 28

(8x - 4y) + (5x + 4y) = 28 + 11

8x + 5x - 4y +4y = 39

13x = 39

x = 3

Hence, x = 3, and y = -1 (5x = 15, 11 - 15 = -4, -4 / 4 = -1)

Hope this helped!

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In a purse there are 30 coins, twenty one-rupee and remaining 50-paise coins. Eleven coins are picked simultaneously at random a
Masteriza [31]
The solution to the answer is as follows:


<span>0votes</span><span>answered <span>Aug 8, 2015 </span><span><span>by </span>Shashi Kumar Evangelist <span>(3,082<span> points)</span></span></span></span><span>total coins 30
1 rupee coins 20
50 paise coins 10

1 rupee coin probability 20C11
11 coin are picked 30C11
<span>ans should be = 20C11/30C11 = 2/3</span></span>
I hope my answer has come to your help. God bless and have a nice day ahead!
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