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igomit [66]
3 years ago
14

Solve each system by elimination. X+6y=-8 7x+2y=24

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0

Answer:

y=-2

x=4

Step-by-step explanation:

equation 1: x + 6y = -8

equation 2: 7x + 2y = 24

To eliminate x first, multiply equation 1 by 7:

7x + 42y = -56

Then subtract the equations from each other:

{ 7x + 42y = -56 } - { 7x + 2y = 24 } = -40y=80

Then we divide both sides by -40 to isolate the <em>y</em>

y = -2

Then we plug -2 into y in one of the equations to find <em>x</em>:

7x+42y=-56

7x+42(-2)=-56

7x-84=-56

7x=28

x=4

adoni [48]3 years ago
3 0

Answer:

8x + 8y = 24

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kherson [118]

Answer:

5 and 6

Step-by-step explanation:

7 0
3 years ago
I have 200 coins to put into 4 bags I put the coins into each bag so that each bag has 2 mote coins than the one before How many
Allushta [10]

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

<em><u>Solution:</u></em>

Given that,

Total number of coins = 200

Number of bags = 4

<em><u>I put the coins into each bag so that each bag has 2 more coins than the one before</u></em>

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found

4 0
3 years ago
Is -0.25 rattional or irrational
sattari [20]
The answer is rational
3 0
2 years ago
In circle S with m ∠ R S T = 98 m∠RST=98 and R S = 4 RS=4 units, find the length of arc RT. Round to the nearest hundredth.
user100 [1]

Answer:6.84

Step-by-step explanation:

:)

7 0
2 years ago
Identify the lateral area and surface area of a regular triangular pyramid with base edge length 14 cm and slant height 15 cm
posledela

Answer:

D) L = 315 cm2 ; S = 399.9 cm2

Step-by-step explanation:

Lateral area;

3 × (½)(14)(15)

315 cm²

Surface area:

315 + (½)(14)(14)sin(60)

399.8704896 cm²

6 0
3 years ago
Read 2 more answers
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