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4 years ago

What is the average speed of an object that travels 50 miles in 2 hours?

2 answers:

8 0

Just divide the total distance traveled (50 miles) by the elapsed time (2 hours):

50 miles
------------ = 25 mph
2 hours

PolarNik [594]4 years ago

7 0

25 mph
just divide by 2

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PLEASE HELP ASAP

Vilka [71]

Answer:

A, 152 cm.

Step-by-step explanation:

A rectangular pyramid has a volume equation of

V = (lwh)/3.

Therefore, when we plug the values in:

[(7)(5)(13)]/3 = V

V = 455/3

V = 151.666667

V is approximately equal to 152 cm^3.

I hope this helped! :)

5 0

2 years ago

Plz help me out with this and do show work I will be waiting.... btw u will be marked brainliest!!!!!! Fast plz

pychu [463]

Answer:

x=16°

Step-by-step explanation:

5*x-30=2*(x+18)

For the second, I'd say it is:

5*x-30=2*x+18

Let's solve both.

5*x-30=2*(x+18)

5x-30=2x+36

3x=66

x=22

5*x-30=2*x+18

3x+48

x=16°

8 0

3 years ago

If it is now 5:00 AM, what time will it be in 1000 hours

VikaD [51]

Answer:

9:00pm

Step-by-step explanation:

If now is 5:00 am

After 1000hrs

24hrs makes a day

1000hrs = 1000/24 = 41 days remainder 16hrs

Therefore 5:00 + 16 hrs = 2100 hr

= 9:00pm

I hope this was helpful, please mark as brainliest

5 0

3 years ago

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.

n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p= $-0. 4t^2+128t+1,200$

For population to disappear, p =0

$-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115$

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

7 0

1 year ago

What is the ratio of 5:3

Varvara68 [4.7K]

5:3

5 to 3

5/3

Is that what you are looking for?

4 0

3 years ago