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gregori [183]
3 years ago
12

What is the average speed of an object that travels 50 miles in 2 hours?

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0
Just divide the total distance traveled (50 miles) by the elapsed time (2 hours):

50 miles
------------ = 25 mph
 2 hours
PolarNik [594]3 years ago
7 0
25 mph
just divide by 2

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25. An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this
Viktor [21]

Answer:

a. 144 ft

b. 5 s

Step-by-step explanation:

h = -16t² + 64t + 80

a. This is a parabola, so the maximum height is at the vertex.

t = -64 / (2 × -16)

t = 2

h = -16(2)² + 64(2) + 80

h = 144

The apple reaches a maximum height of 144 ft.

b. 0 = -16t² + 64t + 80

0 = t² − 4t − 5

0 = (t + 1) (t − 5)

t = -1 or 5

t must be positive, so it takes 5 seconds to reach the ground.

3 0
3 years ago
Which expression has a value less than 32? 32*4/3. Or 32 • 3/4. Or 32* 3/4 or 32 * 5/2
ValentinkaMS [17]
I would say 32 <span>• 3/4 or 32* 3/4 

</span>
7 0
3 years ago
Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
ElenaW [278]
<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

Or as ordered pairs: (\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)

<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

6+y+y^2=6

y^2+y=0

y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

- For y=0

x^2=6+y

x^2=6

x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

6 0
3 years ago
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The answer seems to be 108
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