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kaheart [24]
3 years ago
12

Imagine tossing a coin what are your chances for tossing a head?

Mathematics
2 answers:
natita [175]3 years ago
6 0
50% of having it land one heads
Sav [38]3 years ago
3 0

50 percent there are two sides of the coin and if you were to randomly flip it would be 1/2=50%


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1. Find the sum. -5 + ( -1 ) + 6 + 4
Alex73 [517]
<span>1. Find the sum. -5 + ( -1 ) + 6 + 4

</span> -5 + ( -1 ) + 6 + 4 
= -5 -1 + 10
= 4
answer <span>B: 4

</span><span>2. Add -10 + ( -5 ) + 15
</span><span> -10 + ( -5 ) + 15
= -10 - 5 + 15
= -15 + 15
= 0

answer
</span><span>B: 0</span>
8 0
4 years ago
Read 2 more answers
What is the area of that figure??
pochemuha

Answer:

It's 51 square inches. You can multiply 12x8 and subtract 9x5 from that.

4 0
3 years ago
Bailey studies 3 days for her final exam in history. The first day she studied 1 1/2 hours on day 2 she studied 1/2 as long as s
borishaifa [10]
1st day: 1 1/2 hours
2nd day: half of first day = 1/2 * 1 1/2 hours
3rd day: 2 1/2 times as long as first day: 2 1/2 * 1 1/2 hours

1 1/2 + 1/2 * 1 1/2 + 2 1/2 * 1 1/2 =

= 3/2 + 1/2 * 3/2 + 5/2 * 3/2

= 3/2 + 3/4 + 15/4

= 6/4 + 3/4 + 15/4

= 24/4

= 6

Answer: She studied for 6 hours over the 3-day period.
5 0
3 years ago
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Find the area of a regular hexagon if given a side length of 1.9 to the square root of 3.
dalvyx [7]

Answer:

28.137 sq. units.

Step-by-step explanation:

Area of a regular hexagon is

A=\dfrac{3\sqrt{3}}{2}a^2

where, a is the side length.

It is given that the side length of the regular hexagon is 1.9\sqrt{3}.

Substitute a=1.9\sqrt{3} in the above formula.

A=\dfrac{3\sqrt{3}}{2}(1.9\sqrt{3})^2

A=(1.5\sqrt{3})(10.83)

A=16.245\sqrt{3}

A=28.137

Therefore, the area of regular hexagon is 28.137 sq. units.

6 0
3 years ago
What is the interquartile range of this data set 10,12,16,
Mademuasel [1]
The answer is 6.

Ignore this I’m just typing for more letters
7 0
3 years ago
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