3 years ago

How do i answer this question and where do i put the line

Mathematics

1 answer:

balandron [24]3 years ago

8 0

Answer:

4'4

Step-by-step explanation:

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steps to solve

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Move the -5 over by adding 5 to both sides
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for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
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x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
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remember that√-1=i
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x= $\frac{-2+ i\sqrt{-11} }{3}$ or x= $\frac{-2- i\sqrt{-11} }{3}$

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