Answer:
the teacher bought 100 balloons, and 95 of them were left for the party.
Step-by-step explanation:
red balloons is given, 40.
first you find the green balloons.
<em>the number of green balloons is 3/5 the number of red balloons.</em>
3/5 * 40 = 24
so there are 24 green balloons.
next is yellow balloons.
<em>the number of green balloons is 2/3 the number of yellow balloons.</em>
24 = 2/3 * x
24 ÷ 2/3 = x
24 ÷ 2/3 = 36
there are 36 yellow balloons.
find the total balloons:
40 + 24 + 36 = 100
the teacher bought 100 balloons.
1/20 of the red balloons popped.
1/20 * 40 = 2
2 of the red balloons popped
1/12 of the green balloons popped
1/12 * 24 = 2
2 of the green balloons popped.
1/36 of the yellow balloons popped
1/36 * 36 = 1
1 yellow balloon popped
2 + 2 + 1 = 5
100 - 5 = 95
there were 95 balloons left for the party.
Answer:
x = 16
y = 116
Step-by-step explanation:
Given is a figure of isosceles trapezoid. One pair of opposite sides are parallel and non-parallel sides acts as it's transversals.
Therefore,
4x° + (6x + 20)° = 180° ( interior angles on the same side of transversal)
(6x + 20 + 4x)° = 180°
(10x + 20)° = 180°
10x + 20 = 180
10x = 180 - 20
10x = 160
x = 160/10
x = 16
Measure of base angles of an isosceles trapezoid are equal.
Therefore,
y° = (6x + 20)°
y = 6x + 20
y = 6*16 + 20
y = 96 + 20
y = 116
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
X - Intercept: 3x + 5y = -15
3x + 5(0) = -15
3x + 0 = -15
3x = -15
3 3
x = -5
(x, y) = (-5, 0)
Y - Intercept: 3x + 5y = -15
3(0) + 5y = -15
0 + 5y = -15
5y = -15
5 5
y = -3
(x, y) = (0, -3)
if the upper number got power of negative it will go down and the down will go up
So that,
power of 1 can no need to write
