I'm having trouble with this absolute value question--please help!

7800 dollars is placed in an account with an annual interest rate of 6.5%. How much will be in the account after 29 years, to th

dimaraw [331]

Answer:

Year 29 $2,956.63 Total Interest $40,643.25 Balance $48,443.25

Step-by-step explanation:

Base amount: $7,800.00

Interest Rate: 6.5% (yearly)

Effective Annual Rate: 6.5%

Calculation period: 29 years

4 0

3 years ago

Slope intercepts No links, Will mark BRAINLIEST

Sergeeva-Olga [200]

Answer:

Lines are perpendicular to each other .

Step-by-step explanation:

Standard equation of line is : y = mx + c, Where m represents the slope

Given Equations :

$y = -5x + 1\\\\Slope , m_1 = -5$

$y = \frac{1}{5}x +1\\\\Slope, m_2 = \frac{1}{5}$

Two lines are parallel if the slope of the lines are same.

Two line are perpendicular if the product of the slope = - 1

Clearly slopes are not equal , therefore the lines are not parallel.

product of the slope is - 1, therefore the lines are perpendicular.

$m_1 \times m_2 = -5 \times \frac{1}{5} = - 1$

8 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$