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3 years ago

15

For which pair of triangles would you use SSS to prove the congruence of the 2 triangles?

2 answers:

Nadusha1986 [10]3 years ago

7 0

D) because it's the only one that contains given equal sides in both triangles

Juliette [100K]3 years ago

5 0

In last one, all three sides of one triangle are congruent with all three sides of another triangle.

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john is looking at a map with a scale of 1/4 inch=20 miles. he measured the distance from his home to the bowling alley in town

Sergio039 [100]

1 inch=80mi

2.5*80mi=200 mi

5 0

2 years ago

The key idea of the transformation called a reflection is the rotating of a plane about a fixed point. true or false

Dennis_Churaev [7]

Answer: The answer is true your welcome

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve for x. 5 x − 19 ≤ 1 OR − 4 x + 3 < − 6

k0ka [10]

$5x - 19 \leqslant 1$

change

$\leqslant \: to \: =$

given you

$5x - 19 = 1$

making x the subject by transferring the -19 to the right hand side of the equation

$5x = 19 + 1$

$5x = 20$

dividing through by 5

$\frac{5x}{5} = \frac{20}{5}$

$x = 4$

{ ${x:x \leqslant 4}$ }

also given

$- 4x + 3 < - 6$

change the operation sign to =

$- 4x + 3 = - 6$

$- 4x = - 6 - 3$

$- 4x = - 9$

dividing through by -4

$\frac{ - 4x}{ - 4} = \frac{ - 9}{ - 4}$

$x = \frac{9}{4}$

so the truth set is

{x:x>9/4}.

The < sign changes to > because we divided by a negative number when solving for x

4 0

3 years ago

Find the area. Round to the nearest whole number.

Leona [35]

Answer:

23.

the answer is 33. But when i round its 23.

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

coldgirl [10]

Answer:

z = -0.4.

Step-by-step explanation:

Here's the formula for finding the z-score (a.k.a. standardized normal variable) of one measurement $x$ of a normal random variable $X \sim N(\mu,\; \sigma^{2})$ :

$\displaystyle z = \frac{x-\mu}{\sigma}$ ,

where

$z$ is the z-score of this measurement,
$x$ is the value of this measurement,
$\mu$ is the mean of the random normal variable, and
$\sigma$ is the standard deviation (the square root of variance) of the random normal variable.

Let the length of a trout in this lake be $X$ inches.

$X \sim N(30, \; 4.5^{2})$ .

$\mu = 30$ , and
$\sigma = 4.5$ .

For this measurement, $x = 28.2$ . Apply the formula to get the z-score:

$\displaystyle z = \frac{x - \mu}{\sigma} = \frac{28.2 - 30}{4.5} = -0.4$ .

5 0

2 years ago