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3 years ago

Can someone please help me with this question?

Mathematics

1 answer:

White raven [17]3 years ago

4 0

Answer:

B. Lynden

Step-by-step explanation:

4(2x+2) - 2(x + 2) = 10 - 3(x +2)

To use the distributive property, you multiply the terms inside the parentheses by the number outside them.

8x + 8 - 2x - 4 = 10 - 3x - 6

A is wrong. Gregory used the addition property incorrectly. He should have gotten

4(2x + 2) + (x + 2) = 10

C is wrong. Whitney used the distributive property incorrectly. She made a mistake when distributing the -2 in -2(x + 2). She should have gotten

8x + 8 - 2x - 4 = 10 - 3x - 6

D is wrong. David combined like terms incorrectly. 10 and 3x are not like terms. He should have gotten

4(2x + 2) - 2(x + 2) = 4 - 3x

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Lee wants to gain 10lbs of lean muscle mass. His dietitian suggested the consume 2400 kcal each day and that 25% of his cal come

goldfiish [28.3K]

Answer:

a) He needs to consume 600 kcal from protein.

b) 22 kcal come from fat.

Step-by-step explanation:

a) Lee needs to consume 2400 kcal each day and 25% of this income should come from protein.

We are going to use percentages to solve this problem, to find out how many kcal from protein he should consume we need to multiply 2400 by .25.

2400 (.25) = 600

Lee needs to consume 600 kcal from protein.

b) A cup of chili contains 220 kcal If 15% of kcal come from fat how many kcal come from fat?

We are going to solve this in a similar way.

We should multiply the total amount of kcal by .15 which is the amount of fat calories.

220 (.15) = 33

33 kcal come from fat.

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3 years ago

Fill in the blank. (Simplify your answer completely.) The midpoint of a line segment joining (a, b) and (c,d) is given by the fo

IrinaVladis [17]

Answer:

The midpoint of a line segment joining (a, b) and (c,d) is given by the formula $(\frac{a+c}{2},\frac{b+d}{2} )$

Step-by-step explanation:

If point M in the figure lies midway between points $P(x_{1},y_{1})$ and $Q(x_{2},y_{2})$ , point M is called the midpoint of segment. To find the coordinates of M, we average the x-coordinates and average the y-coordinates of P and Q.

So the the midpoint of the line segment with endpoints at (a,b) and (c,d) is the point with coordinates of

$(\frac{a+c}{2},\frac{b+d}{2} )$

6 0

3 years ago

What is the LCD of 5/12 and 3/8

Ber [7]

24 is the LCD of 5/12 and 3/8

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cint%5C%20%28x%5E3-6x%5E2%2B9x%2B3%29%283x%5E2-12x%2B9%29%20dx" id="TexFormula1" title="\int

AlexFokin [52]

If the integral is simply

$\displaystyle\int(x^3-6x^2+9x+3)(3x^2-12x+9)\,\mathrm dx$

then notice that

$\mathrm d(x^3-6x^2+9x+3)=(3x^2-12x+9)\,\mathrm dx$

which means you can compute the integral easily with a substitution

$u=x^3-6x^2+9x+3\implies\mathrm du=(3x^2-12x+9)\,\mathrm dx$

Under this transformation, the integral is

$\displaystyle\int u\,\mathrm du=\frac{u^2}2+C=\boxed{\frac{(x^3-6x^2+9x+3)^2}2+C}$

On the other hand, in case you're missing a symbol and the integral is actually

$\displaystyle\int\frac{x^3-6x^2+9x+3}{3x^2-12x+9}\,\mathrm dx$

then first carry out the division:

$\dfrac{x^3-6x^2+9x+3}{3x^2-12x+9}=\dfrac x3-\dfrac23-\dfrac{2x-9}{3x^2-12x+9}$

Now, $3x^2-12x+9=3(x-3)(x-1)$ , so to integrate the remainder term you can decompose it into partial fractions:

$-\dfrac{2x-9}{3(x-3)(x-1)}=\dfrac a{x-3}+\dfrac b{x-1}$

$9-2x=a(x-1)+b(x-3)$

$x=1\implies7=-2b\implies b=-\dfrac72$

$x=3\implies3=2a\implies a=\dfrac32$

$\implies-\dfrac{2x-9}{3(x-3)(x-1)}=\dfrac 3{2(x-3)}-\dfrac 7{2(x-1)}$

Then the integral would be

$\displaystyle\int\frac{x^3-6x^2+9x+3}{3x^2-12x+9}\,\mathrm dx=\boxed{\frac{x^2}6-\frac{2x}3+\frac32\ln|x-3|-\frac72\ln|x-1|+C}$

which can be rewritten in several ways, such as

$\dfrac{x^2-4x}6+\dfrac12ln\left|\dfrac{(x-3)^3}{(x-1)^7}\right|+C$

6 0

3 years ago

Can someone help me solve (x+18)^(1/2)+2=x

____ [38]

Lets solve your equation step by step:
(x+18)^1/2+2=x
step 1:Add -2 to both sides:
(x+18)^1/2+2-2=x+-2
(x+18^)1/2=x-2
step 2:solve exponent
(x+18)^1/2=x-2
((x+18)^1/2)^2=(x-2)^2
x+18=x^2-4x+4
x+18-(x^2-4x+4)=x^2-4x+4-(x^2-4x+4) (subtract x^2-4x+4 from both sides)
-x^2+5x+14=0
(-x-2)(x-7)=0(factor left side of equation)
-x-2=0 or x-7=0 (set factors equal to zero)
x=-2 or x=7

check answers:(plug them in to make sure they work )
x=-2(doesn't work in original equation)
x=7(works in original equation)

6 0

3 years ago