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Alex
3 years ago
9

WHAT NUMBER IS MISSING IN THE FOLLOWING SERIES: 4 --‐ 5 --‐ 7 --‐ 10 --‐ 14 --‐ 19 --‐ ___

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

25

simple, when you add another number into the sequence, it is increased by 1 per each number...

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Hellllllllllllllllllllllllpppppppppppppppppppppppp
Marizza181 [45]

Answer:

A) 200 students

B) 24

C) 46%

D) 46% are driven by car

Step-by-step explanation:

5 0
3 years ago
Help me with this plzzzzz I need to finish it rn so PLZZ help asp
garri49 [273]

Answer:

1. 16π

2. 112π

3. 351.68

Step-by-step explanation:

Area of a circle = πr^2

Substitute...

=4^2π

=16π

To find the how much fluid it can hold, just basically find its volume. To do that, you mutiply the area of the base by the height. So...

16π*7=122π

You then just subsitute π by 3.14 so...

122(3.14)=351.68

4 0
3 years ago
PLEASE HELP 7TH GRADE MATH
eimsori [14]
Oof... you will need 46,656 to get all 6 prizes .... Throw a die.
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5 0
3 years ago
Please help, When do you need to approximate an irrational number with a rational value? Explain your understanding and give an
disa [49]

9514 1404 393

Answer:

  in any numerical computation; numerical values can only be rational numbers

Step-by-step explanation:

Any time a number is written down as a numerical value, it is a rational number. The numerical values we give to π or e or any root, logarithm, trig function, and polynomial solution are, of necessity, rational approximations to the true value. An "exact" value for an irrational number cannot be written down, so it must be approximated any time its numerical value is needed.

8 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
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