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GuDViN [60]
3 years ago
14

Two soccer balls are simultaneously kicked on parallel paths, from 15 feet apart on level ground. After 0.1 second, the balls ar

e again 15 feet apart. 15 ft Must the two soccer balls have traveled the same distance in the first 0.1 second after they were kicked? If so, which theorem or definition can you use to show this? HELP QUICK WORTH 100 POINTS
Mathematics
2 answers:
mylen [45]3 years ago
8 0

Answer:

They do not have to always be 15 feet apart

Step-by-step explanation:

Becuase if they were kicked by different

people, then they might have different forces behind them and one could travel farther.

Gnesinka [82]3 years ago
6 0

Answer:c i belive

Step-by-step explanation:

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The score on a trivia game is obtained by subtracting the number of incorrect answers from twice the number of correct answers.
guajiro [1.7K]

Answer: the player answered 30 questions correctly.

Step-by-step explanation:

Let x represent the number of questions that the player answered correctly.

Let y represent the number of questions that the player answered incorrectly.

The number of questions that the player answered is 40. It means that

x + y = 40- - - - - - - - - - -1

The score on the trivia game is obtained by subtracting the number of incorrect answers from twice the number of correct answers. If the player obtained a score of 50, It means that

2x - y = 50

y = 2x - 50

Substituting y = 2x - 50 into equation 1, it becomes

x + 2x - 50 = 40

3x - 50 = 40

3x = 40 + 50 = 90

x = 90/3

x = 30

5 0
4 years ago
To control an infection, a doctor recommends that a patient who weighs 92 pounds be given 320 milligrams of antibiotic. If the a
stich3 [128]

Answer:

480 milligrams.

Step-by-step explanation:

Divide 320 by 92, you get 3.47826087, multiply that by 138 to get your answer (480).

7 0
3 years ago
Read 2 more answers
100^a x 1000^b can be written in the form 10^w <br><br> Show that w = 2a + 3b
Elena L [17]
100^a \time 1000^b = 10^{2a} \times 10^{3b} = 10^{2a + 3b}

10^{w} = 10^{2a + 3b}

w = 2a + 3b \text { (shown)}
3 0
3 years ago
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

4 \frac{1}{2sin(x)cos(x)}

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}

2\frac{sin(x)}{sin^2(x)cos(x)}

2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}

We know that sinx/ cosx = tan(x)

Also  1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified



6 0
3 years ago
Thanks if you help.....
marissa [1.9K]

Answer:

I'm guessing it's D.

Step-by-step explanation:

Sorry if wrong :> Hope i helped! Have a awesome day!!! You're a great hooman ^_^ Please mark brainliest !!

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