Rover has dug 4 holes and put b bones in each hole. He finds 5 more bones. How many bones does Rover have?

I need help with this question? Please and thank you!!!!<br> #15

4vir4ik [10]

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7 0

3 years ago

Read 2 more answers

How to do this question plz answer me step by step plzz

finlep [7]

Answer:

30, 85, 95, 150

Step-by-step explanation:

The angles of a quadrilateral add to 360

Let x be the smallest angle

x+55

x+65

x+120 are the other three angles

Add the 4 angles together and they sum to 360

x+x+55 x+65+ x+120 = 360

Combine like terms

4x+240 = 360

Subtract 240 from each side

4x+240-240 = 360 -240

4x = 120

Divide by 4

4x/4 = 120/4

x = 30

x+55= 30+55 = 85

x+65 = 30+65 = 95

x+120 = 30+120 = 150

7 0

3 years ago

1/5 of the shoes in a factory are green. If you pick a shoe, replace it, pick another shoe and replace it, and pick a third shoe

Bogdan [553]

Answer: I believe it’s 3/5

Step-by-step explanation:

5 0

2 years ago

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Which of the following points lie in the solution set to the following system of inequalities?

laiz [17]

Answer:

B. (5,-2)

Step-by-step explanation:

Plug in X and Y, verify accuracy

7 0

3 years ago

A study by the Pew Research Center1 reports that in 2010, for the first time, more adults aged 18 to 29 got their news from the

sergejj [24]

Answer:

Null hypothesis: $p \leq 0.65$

Alternative hypothesis: $p > 0.65$

$z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812$

$p_v =2*P(z>0.812)=0.208$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the adults that said television was one of their main sources of news.

$\hat p=0.66$ estimated proportion of adults that said television was one of their main sources of news.

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.65:

Null hypothesis: $p \leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>0.812)=0.208$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.

Do we find evidence that more than 65% of all US adults use television as one of their main sources for news?

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

6 0

3 years ago