I got a hold on hood for the
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
Answer:
= 8.9 units
Step-by-step explanation:
When a chord intersects with a tangent outside a circle then we use the relationship;
X ² = AO × BO, Where A and are the points of intersection of the chord an the circle, while O is the point of intersection between the chord and the tangent.
Therefore;
x² = 4 × 20 or 8 × 10
x² = 80
x = √80
= 8.944
≈ 8.9
Answer:
B.
Step-by-step explanation:
A²-5a+6
to factorise you find the common numbers that add to make 5 and times to make 6
soo that means it is
(a-2) (a-3)
