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3 years ago

A bag contains 6 blue coins and 7 red coins. A coin is removed at random and replaced by three of the other color.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

5 0

1/4 or maybe even 100grams of blow

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3(x - 4) + 9 = 18<br><br> Step by step (and explanation)

Andrews [41]

Answer:

= 7

Step-by-step explanation:

3(x−4)+9=18

3 − 1 2 + 9 = 1 8

3 − 3 = 1 8

3 = 1 8+3

3 = 21

x= 21/3

x=7

3 0

3 years ago

A number w decided by 5 equals 6

Harman [31]

Answer:

You write the question wrong but it's okay

Step-by-step explanation:

it will be 30

i hope my answer help you

8 0

3 years ago

Read 2 more answers

Please help me with this

swat32

Answer:

The answer is 156.25π or about 490.625

Step-by-step explanation:

To find the area of a circle, you use the formula πr² (pi times radius times radius.) The radius is 12.5, so you plug it in to the equation. Once you plug the radius into the equation, you get π times 12.5 times 12.5. This simplifies to 156.25 times pi. If you want to use 3.14 as pi, the final answer is about 490.625. I hope this helps and that you have an fantastic day!!! Hope you stay safe!!!

6 0

3 years ago

The slope of the line below is 2. Use the coordinates of the labeled point to find a point-slope equation of the line.

Vanyuwa [196]

Y - 9 = 2(x - 1)

This is because the base equation is below:

y - y1 = m(x - x1)

3 0

3 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago