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2 years ago

A coat is on sale for 65% of the original price of $58. Calculate the sale price. Explain please

Mathematics

2 answers:

lys-0071 [83]2 years ago

5 0

Answer:

$37.70

Step-by-step explanation:

65 divided by 100 multiplied by $58 is $37.70

liraira [26]2 years ago

4 0

Answer:

37.7

Step-by-step explanation:

Discount = original price * percent off

The percent is 65% of the original price

The percent off is 100-65 = 35%

Discount = 58* 35%

= 58 * .35

=20.3

Sale price = Original price - discount

= 58-20.3

=37.70

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4000-1375 and I need work

zheka24 [161]

4000
-1375
———

Take 1 from the number 4 and have it go down the line of zeros.

39910
-1375
———-

Subtract

39910
-1375
———-
2,625

I hope this helped!

8 0

3 years ago

The fifth graders to plant a butterfly garden. Clover grows in ½ of the garden, daisies in ¼ of the garden, coneflowers in ⅛ of

olchik [2.2K]

Answer:

Fraction of the garden used = $\frac{5}{8}$

Step-by-step explanation:

The fifth graders to plant a butterfly garden.

We are given that

Clover grows in ½ of the garden

Daisies grow in ¼ of the garden

Coneflowers grow in ⅛ of the garden

milkweed grows in ⅛ of the garden

The fifth graders notice that the butterflies land on the clover and milkweed.

We are asked to find out the fraction of the garden that the butterflies used.

Fraction of the garden used = clover + milkweed

Fraction of the garden used = $\frac{1}{2} + \frac{1}{8}$

The LCM of 2 and 8 is 8

Fraction of the garden used = $\frac{4 +1}{8}$

Fraction of the garden used = $\frac{5}{8}$

Therefore, the butterflies used $\frac{5}{8}$ fraction of the garden.

6 0

2 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have