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olga_2 [115]
2 years ago
9

A coat is on sale for 65% of the original price of $58. Calculate the sale price. Explain please

Mathematics
2 answers:
lys-0071 [83]2 years ago
5 0

Answer:

$37.70

Step-by-step explanation:

65 divided by 100 multiplied by $58 is $37.70

liraira [26]2 years ago
4 0

Answer:

37.7

Step-by-step explanation:

Discount = original price * percent off

The percent is 65% of the original price

The percent off is 100-65 = 35%

Discount = 58* 35%

               = 58 * .35

                 =20.3

Sale price = Original price - discount

                   = 58-20.3

                    =37.70

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Answer:

H > 2.5

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Greater = >

Lessthan = <

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Consider testing H^0: u=20 against H^a: u&lt;20 where u is the mean number of latex gloves used per week by all hospital employe
iragen [17]

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Part a: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

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Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

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Step-by-step explanation:

Data given and notation  

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s=11.8 represent the sample standard deviation

n=46 sample size  

\mu_o =20 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

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We can replace in formula (1) the info given like this:  

t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517    

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The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

p_v =P(t_{(45)}  

Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

a. There is insufficient evidence to reject h^0

5 0
2 years ago
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