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Sever21 [200]
3 years ago
9

10 times the square root of 5

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

22.36

or 559/25

or 22 9/25

Step-by-step explanation:

Calculator

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3 0
3 years ago
In a random sample of 25 ​people, the mean commute time to work was 33.9 minutes and the standard deviation was 7.2 minutes. Ass
Phoenix [80]

Answer:

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

33.9+1.32\frac{7.2}{\sqrt{25}}=35.801    

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}}

And replacing we got:

ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=33.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=7.2 represent the sample standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=25-1=24

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,24)".And we see that t_{\alpha/2}=1.32

Now we have everything in order to replace into formula (1):

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

33.9+1.32\frac{7.2}{\sqrt{25}}=35.801    

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}}

And replacing we got:

ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008

   

7 0
4 years ago
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