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Lina20 [59]
3 years ago
5

1) what are two functions of a pick or count condition?

Computers and Technology
1 answer:
viktelen [127]3 years ago
3 0
1.  The best option is C) pick an object at random, and keep track of how many copies of an object are left in a game.
2.   The best option is D) clockwise and counterclockwise.
3.    your 3rd question does not seem to be clear to me.
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Hacking to send a political message
Crank

Answer:

Good for you

Explanation:

But I dont get this

4 0
4 years ago
Carina is concerned that her computer is slowing down because it doesn’t have enough short-term memory. Which of the following s
steposvetlana [31]
I would say I think RAM? Hope this helps;)
8 0
3 years ago
Read 2 more answers
Create a Racket procedure compute_pos that reads numbers from the keyboard until 0 is read, count how many positive numbers are
Artyom0805 [142]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {

       compute_pos();

     }

     

     public static void compute_pos(){

     Scanner scan = new Scanner(System.in);

     int sum = 0;

     int counter = 0;

     // Prompt the user to enter an input

     System.out.println("Enter your value");

     // user input is assign to the variable value

     int value = scan.nextInt();

     

     while(value != 0){

         if (value > 0){

             sum += value;

             counter++;

         }

         System.out.println("Enter your value");

         value = scan.nextInt();

     }

     // Display the value of sum to the user

     System.out.println("The sum of the positive number is: " + sum);

     // Display the value of counter to the user

     System.out.println("The number of positive number is: " + counter);

   }

}

Explanation:

The first line import the Scanner class which allow the program to read input from the user. The class Solution is then defined. Then the main method which signify the beginning of execution in the program is defined. A method is called inside the main method.

The method compute_pos is defined. Inside the compute_pos method, a scanner object scan is declared to accept input from the user via the keyboard.

The variable sum and counter is declared and assigned to 0.

A prompt is displayed to the user to input a value. The user input is accepted and stored in the variable value.

Then a while loop is use to check the user input if it is not equal to zero. If it is equal to zero, the loop will end. Inside the loop, we first check to see if the user input is greater than 0, if it is, we add it to the variable sum and increase our counter by 1. At the end of the loop, a prompt is again display to accept input from the user.

Outside the loop, we display the sum and counter to the user.

8 0
4 years ago
Write a MIPS program to continuously generate the following series of integers: 1, 2, 3, 6, 9, 18, 27, 54, 81, and so on. Use st
Pachacha [2.7K]

Answer:

Explanation:

Here is a working solution in MIPS

.data

space: .asciiz ", "

.text

li $t1, 1       #Start at 1

li $t2, 1       #Store last value

li $t4, 1000    #terminate at 1000

li $t7, 2       #For division (divide by 2)

loop:

li $v0, 1

add $a0, $t1, $zero #print $t1

syscall

div $t1, $t7      #divide $t1 by 2

mfhi $t5          #get the remainder

move $t6, $t1     #hang on to what $t1 was originally

beqz $t5, even    #if the remainder is 0, it's even

add $t1,$t1,$t1    #it's odd, so add to itself

move $t2, $t6      #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4           #Print a comma and space

la $a0, space

syscall

j loop

even:

add $t1,$t1,$t2    #set $t1 = $t1 + Last value ($t2)

move $t2, $t6      #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4           #Print a comma and space

la $a0, space

syscall

j loop

done:

3 0
4 years ago
You provide desktop support for a small company. The company has two locations in the same city, but they are several miles away
Igoryamba

Answer:

The answer is "Option D".

Explanation:

It is a desktop platform that helps a "client" computer can join from a remote location to a "host" computer. Clients can then manage and then use apps and files anywhere on network protocols.

This technology enables users to link from the remote location to a specific machine as if they were sitting beside it. Once this connection is established, users can carry out a variety of tasks as if they actually use the computer directly.

4 0
3 years ago
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