Floating point numbers?

irina [24]

Answer:A keyboard layout is any specific physical, visual or functional arrangement of the keys, legends, or key-meaning associations of a computer keyboard, mobile phone, or other computer-controlled typographic keyboard.

An output device is any peripheral that receives data from a computer, usually for display, projection

A printer is an output device that prints paper documents. This includes text documents, images, or a combination of both

Laser Printers and LED printers

Explanation:

8 0

2 years ago

A technician is dispatch to troubleshoot a user's computer.

Margarita [4]

Answer:

All of the above.

Explanation:

Thrashing or drive or disk thrashing occurs when the hard drive is stressed with transferring information between the system memory and virtual machine excessively. In thrashing, there is a large number of processes running in the system and the system memory is too small to handle all processes. Thrashing leads to decreased system performance and hard disk failure.

To stop the impact of thrashing, install more RAM, end unimportant progam processes etc.

5 0

3 years ago

Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.

Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is $\mathbf{2^{20}}$ entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

32-bit logical address
Page size = 4 KB = $\mathbf{2^{12} \ bytes }$
Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = $\mathbf{2^{26} \ bytes}$

Thus, the number of bits in the physical address is computed as:

= $\mathbf{log_2 \{Physical-memory-size\}}$

$=\mathbf{log_2(2^{26})}}$

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table $\mathbf{= \dfrac{2^{32}}{2^{12}}}$

$\mathbf{=2^{20}}$ entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= $\mathbf{2^{20}\times 4 \ bytes}$

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is $\mathbf{2^{20}}$ entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

#SPJ1

4 0

1 year ago

in c Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the li

Fiesta28 [93]

Answer:

see explaination

Explanation:

//Include required header file.

#include <stdio.h>

//Define the function isWordContainChar() having the

//required parameters.

int isWordContainChar(char* req_word, char search_char)

{

//Declare required variable.

int i;

//Start a for loop to traverse the string given in

//the function parameter.

for(i = 0; req_word[i] != '\0' ; i++)

{

//If the current character in the gievn word is

//matched with the character which needs to be

//found in the word, then return 1.

if(req_word[i] == search_char)

{

return 1;

}

//Otherwise, return 0.

return 0;

}

//Start the execution of the main() method.

int main(void)

{

//Declare the required variables.

int num_words, index, word_index;

char str_word[20][10];

char searchCharacter;

//Prompt the user to enter the number of words.

scanf("%d", &num_words);

//Prompt the user to enter the required words using a

//for loop and store them into an array.

for(index = 0; index < num_words; index++)

{

scanf("%s", str_word[index]);

}

//Prompt the user to enter a required character which

//needs to be found in a word.

scanf(" %c", &searchCharacter);

//Traverse the words stored in the array using a for

//loop.

for(index = 0; index < num_words; index++)

{

//Call the function isWordContainChar() with

//required arguments in rach iteration and if the

//value returned by this function is not 0, then

//display the current string in the array.

if(isWordContainChar(str_word[index],

searchCharacter) != 0)

{

printf("%s\n", str_word[index]);

}

return 0;

}

3 0

2 years ago

I need help here thanks forever who helps

lubasha [3.4K]

Answer:

the horse, the man, and the cactus

Explanation:

The horse is running

The man got slung off the horse, so its in motion

The cactus is flying everywhere from the horse.

3 0

1 year ago