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trapecia [35]
3 years ago
12

3 and 3/5 divided by 1 and 1/3

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

2 and 7/10

Step-by-step explanation:

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What additional information is needed to prove the triangles are congruent by SAS ?
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Answer: Its EB≅CB

Step-by-step explanation: I took the test

5 0
2 years ago
80% of what # is 16?
liraira [26]
80% of x = 16
"of" translates to multiplication and 80% becomes 80/100.

80/100 × x = 16

0.8x = 16

0.8x/0.8 = 16/0.8

x = 16/0.8

x = 20


Your final answer is 80% of 20 is 16.
4 0
3 years ago
Please help me <br> I will give brainlist please explain
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So you have to graph that on to the chart i think
3 0
3 years ago
I need help with these three problems (college algebra)
Paraphin [41]

5. After 6 hours, the concentration is halved. After 12 hours, it will be quartered. If the original concentration is 200 nmol, a quarter is 50 nmol.

14. The population doubles after 3 hours, and a day is 24 hours. That means that the original population should be multiplied by 2^{24/3}, or 2^8. 3 million times 2^8 is 3 * 256 million, or 768 million.

15. The concentration is halved every 8 hours and the original concentration is 100 nmol. So now, how many times do you halve 100 to get to 12.5?

100/2 = 50, 50/2 = 25, 25/2 = 12.5. That's three times. 3 * 8 is 24 hours, or 1 day.

8 0
3 years ago
Read 2 more answers
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
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