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3 years ago

3m + 4m = 42 Please help. I think the answer is either 7 or -42

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

7 0

7m=42 thus m=6
Because 42/7=6

SOVA2 [1]3 years ago

3 0

Heres what i got
3m+4m=42
7m=42
m=6

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If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

2 years ago

Pls can someone pls help me <br> Please show your work

Lana71 [14]

Answer:

x = 8

I dunno what the question is in the first place, but I assume you are solving for x.

Step-by-step explanation:

The two given angles are equivalent because they are parallel and they have a line that intersects.

The line creates two angles on each side of each line, which is 120 or 60 because there are 180 degs on a straight line.

The obtuse side is 120, and the -8 + 16x is also on an obtuse angle, showing that they are equal.

120 = -8 + 16x

128 = 16x

8 = x

x = 8

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2 years ago

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rjkz [21]

The 2 because we don't know if it is exactly two or if was was rounded up/ down to 2.

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3 years ago

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agasfer [191]

Answer:

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Step-by-step explanation:

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alina1380 [7]

Answer:

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