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3 years ago

Can 19/23 be simplified because my teacher said it can but I say I can not be simplified

Mathematics

2 answers:

mihalych1998 [28]3 years ago

8 0

I agree with you you both of those are prime numbers so it cant be simplified

Snowcat [4.5K]3 years ago

7 0

Hlo mate :-

Problem solution :-

________________________________________________________________________________________________

A/c to me

● You and your teacher both are Right but In different situations and they are :-

☆ You can simply simplify it by division and u will get a ans in decimal

☆ Nd If U don't want to do so then its also right

________________________________________________________________________________________________

☆ ☆ ☆ Hop It's helpful ☆ ☆ ☆

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4/5w-12=2/3w<br> what is the step by step answer to those equation?

Mariulka [41]

Kulay, there is no such thing as a "step by step answer" here. You seem to want a "step by step solution."

I must assume that by 4/5 you actually meant (4/5) and that by 2/3 you meant (2/3). Then your equation becomes:

(4/5)w - 12 = (2/3)w.

The LCD here is 5*3, or 15, so mult. every term by 15:

12w - 180 = 10w.
Add 180 to both sides, obtaining 12 w - 180 + 180 = 10w + 180.

Then 12w = 10w + 180. Simplifying, 2w = 180. What is w?

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3 years ago

Determine which of (a)-(d) form a solution to the given system for any choice of the free parameter. (HINT: All parameters of a

Alecsey [184]

Answer:

Please see attachment

8 0

2 years ago

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A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a

uysha [10]

Answer:

3:4.

Step-by-step explanation:

To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

45 divided by 15 = 3

60 divided by 15 = 4

Therefore the odds of selecting a red candy is 3:4.

Hope that helps. x

7 0

2 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

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2 years ago

Convert 108 centimeters to meters

pogonyaev

108 centimeters equals 1.08 meters

7 0

2 years ago

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