Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16
The cost of p photocopies if each one costs $0.15
Answer:
Step-by-step explanation:
Given the complex notations a = 5i + j, b = i − 2j, we are to evaluate the following:
1) a + b
= 5i+j + (i-2j)
= 5i+j+i-2j
collect like terms
= 5i+i+j-2j
= 6i-j
<em>Hence a+b = 6i-j</em>
2) 2a+3b
= 2(5i+j) + 3(i-2j)
open the parenthesis
= 10i+2j+3i-6j
collect like terms
= 10i+3i+2j-6j
= 13i-4j
<em>Hence 2a+3b = 13i-4j</em>
3) |a| = √x²+y²
Given a = 5i+j; x = 5, y = 1
|a| = √5²+1²
|a| = √25+1
<em>|a| = √26</em>
4) |a-b|
First we need to calculate a-b
= a - b
= 5i+j - (i-2j)
open the parenthesis
= 5i+j-i+2j
collect like terms
= 5i-i+j+2j
= 4i-3j
|a-b| = √4²+(-3)²
|a-b| = √16+9
|a-b| = √25
|a-b| = 5
The answer is B. They did not multiply the constant 2 by 4 when multiplying through to remove the fraction. so the correct answer would be x-4y=-8
