I'm totally not sure but I think sec midterm flashcards
Answer:
Following are the code to this question:
def binarynumber(num):#defining a method binarynumber that accepts a parameter num
x=""#defining a string variable x
if (num!=0):#defining if condition to check number not equal to 0
while (num>=1):#defining a loop that check value is grater then equal to one
if (num %2==0):#defining if condition to check num is even
x=x+"0" #add string value 0 in num variable
num=num/2 #divide the value by 2
else:#defining else block
x=x+"1"#add string value 1 in num variable
num=(num-1)/2#first subtract 1 into num variable then divide the value by 2
else:
x="0"#assign string value 0 in num variable
return "".join(reversed(x))#return value
num = int (input ("Enter any number: "))#defining num variable that input the integer value
print (binarynumber(num))#using print method to call method binarynumber with passing num parameter
Output:
Enter any number: 12
1100
Explanation:
- In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
- Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
- Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
- At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.
Taking the input as a string, slicing it with a space as the delimiter, turning the divided portion into an integer, and then appending to the list.
<h3>
Explanation:</h3>
def selection_sort_descend_trace(numbers):
i=len(numbers)
print("Output: ")
for num in range(0,i-1):# traversing from 0 to N-2, total N-1 iterations
val=numbers[num]
start=num+1
end=i
t=0
for j in range(start,end):
if(val<numbers[j]):
remember=j
val=numbers[j]
t=1
if(t==1):# swaping onlf if greater number is available
temp=numbers[num]
numbers[num]=val
numbers[remember]=temp
for p in range(i):# printing
print(numbers[p],end=' ')
print("\n")
if __name__ == "__main__":
print("Enter the integers separated by space: ")
numbers=[int(x) for x in input().split(' ')]
selection_sort_descend_trace(numbers)
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Answer:
An ACL is a list of permit or deny rules detailing what can or can't enter or leave the interface of a router. Every packet that attempts to enter or leave a router must be tested against each rule in the ACL until a match is found. If no match is found, then it will be denied.
Explanation:
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Answer:
candyCost = int(input("How much is the candy?"))
Explanation:
candyCost = input("How much is the candy?") → By default, this how you get input and store the value. And it is stored as a string
candyCost = str(input("How much is the candy?")) → This also gives you a string to store
candyCost = float(input("How much is the candy?")) → This gives you a float number, decimal number, to store
candyCost = int(input("How much is the candy?")) → This gives you an integer number, a non-decimal
